The hypotenuse of a right triangle is 6 more than twice the shortest side. If the third side is 2 m less than the hypotenuse, find the sides of the triangle.

Let the shortest side be x

Then , hypotenuse = (x+6)

and the third side =(x+6)-2 = (x+4)

By applying pythagoras theorm,

(x+6)² = (x+4)² + x²

x² - 4x - 20=0

Hence, we can find the value of x and hence all the three sides.

Please Approve!